Question

the sum of the digit of a two-digit number 58 and number formed by reversing the digits is less than greater than given number by 18. find the number​

Answer 1

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Let the digit at the tens place be x and the digit at the unit place be y.

x+y=12 ..(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

According to the condition, we get

(10y+x)−(10x+y)=18

→ 9y−9x=18

→ y−x=2 ....(2)

Adding (1) and (2), we get

2y=14 →y=7

→ x= 12 - 7 = 5

Hence, the required number is 57.