the sum of the digit of a two digit number is 15 if the number formed by reversing the digit is less than the original number by 27 find the number
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Answer:
96
Step-by-step explanation:
Let the digits of the number be x and y
Sum of the digits = 15
x + y = 15
x = 15 - y -----(1)
Original number = 10(x) + y = 10x + y ----(2)
New number when the digits are reversed = 10(y) + x = 10y + x
New number is less than the original number by 27
It means : Difference between original number and new number = 27
Equation formed :
10x + y - (10y + x) = 27
10x + y - 10y - x = 27
9x - 9y = 27
9(15 - y) - 9y = 27 (From (1))
135 - 9y - 9y = 27
165 - 18y = 27
135 - 27 = 18y
108 = 18y
108/18 = y
y = 6
Substitute the y = 6 in 1 to get the value of x
x = 15 - 6
x = 9
Substitute x = 9 , y = 6 in (2) to find the number
10(9) + 6 = 90 + 6 = 96
So, 96 is the required number.
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