the sum of the digit of a two digit number is 15.the number obtained by interchangeing the digit exeeds the given number by 9 .find the original number
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Let the digit at ones place be x
The digit at tens place = 15 - x
Number formed = ( 15 - x ) * 10 + x* 1
= 150 - 10x +x
= 150 - 9x
Number formed by interchanging the digit
= x * 10 + ( 15 - x ) * 1
= 10x + 15 - x
= 9x +15
ATQ
=> 9x + 15 = 150 - 9x +9
=> 9x + 9x +15 = 150 + 9
=> 18x +15 = 159
=> 18x = 159 - 15
=> 18x = 144
=> x = 144 ÷ 18
=> x = 8
Therefore, original number = 150 - 9x
=> 150 - 9 * 8
=> 150 - 72
=> 78
The digit at tens place = 15 - x
Number formed = ( 15 - x ) * 10 + x* 1
= 150 - 10x +x
= 150 - 9x
Number formed by interchanging the digit
= x * 10 + ( 15 - x ) * 1
= 10x + 15 - x
= 9x +15
ATQ
=> 9x + 15 = 150 - 9x +9
=> 9x + 9x +15 = 150 + 9
=> 18x +15 = 159
=> 18x = 159 - 15
=> 18x = 144
=> x = 144 ÷ 18
=> x = 8
Therefore, original number = 150 - 9x
=> 150 - 9 * 8
=> 150 - 72
=> 78
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