Question

the sum of the digit of a two digit number is 5 the number obtained by reversing the order of digit diminished the original number by 9 find the number

Answer 1

Answer:let digit at unit place be x and at tens be y so no formed = 10y+x also x+y =5 now when digits are reversed digit at unit place is y so no formed =10x+y now 10y+x-10x+y=9 so 9y-9x=9. Y-x=9 alsoy+x=5 on adding Y=x= 2 so no is 32