Question

the sum of the digit of a two digit number is 9. if the digits are reversed, the number is 63 more than the original. find the number​

Answer 1

Answer:

3 and 6

Step-by-step explanation:

3+6= 9

then

If we reverse it's 63

Answer 2

Answer:

18

Step-by-step explanation:

Let the 2-digit number be 10a+b

So, the sum of digits = a+b = 9                 -------------------(1)

The reversed number = 10b+a

According to the question, 10b+a = 63 + 10a+b

⇒ 9b - 9a = 63

⇒ b-a = 7                                                    ---------------------(2)

On adding equations (1) & (2), 2b = 16 ⇒ b=8

On substituting the value of b in (1), a=1

So, the original number = 18

Hope this helps.....