The sum of the digit of a two digit number is 9. The number obtained by interchanging the digit is 63 more than the original no.?
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tens digit be x and unit digit be y. then x+y=9.also original no. = 10x+y.now 10y+x=63+10x+y. by solving it you will get the answer
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LET THE UNITS DIGIT BE X AND TENS DIGIT BE Y
ORIGINAL NUMBER= 10Y+X
A.T.Q
X+Y=9. ----------------------EQUATION 1
NUMBER OBTAINED BY INTERCHANGING THE DIGIT=10X+Y
10X+Y-(10Y+X)=63
10X+Y-10Y-X=63
9X-9Y=63
9(X-Y)=63
(X-Y)=7. ---------------------EQUATION 2
THEREFORE WHEN WE SOLVE THE EQUATION
THE VALUE OF X IS 8 AND THE VALUE OF Y IS 1
HENCE THE ANSWER IS 18
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