Question

the sum of the digit of a two digital number is 9. the digit in the unit place is 8 times the digit in the ten's place
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Answer 1

Answer:

your answer is 18

Step-by-step explanation:

let the ten's place no. is x

therefore one's place no. = 8 × x = 8x

sum of both digit = 9

a/q,

x + 8x = 9

9x = 9

x = 9/9

x = 1

ten's place no. = 1

one's place no. = 8 × 1 = 8

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