Question

the sum of the digit of the two number is 12 if the new number formed by reversing the digit is greater than the original number by 18 find the original number​

Answer 1

Answer:

57

Step-by-step explanation:

$let \: the \: number \: be = 10x + y \\ x + y = 12 \\ 10y + x > 10 + y \: by \: 18 \\ 10y + x = 10x + y + 18 \\ 10y - y + x - 10x = 18 \\ 9(y - x) = 18 \\ y - x = 2 \\ y = x + 2 \\ also \: x + y = 12 \\ y = 12 - x = x + 2 \\ 2x = 10 \\ x = 5 \\ y = 7 \\ so \\ the \: no \: is \\ 10x + y = 57$

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