Question

the sum of the digit of two digit number is 11. the numbet got by interchangingthe digit is 27 more than the orginal number which are the numbers​

Answer 1

Answer:

the required number is 47

Step-by-step explanation:

let the number in the tens place be x

let the number in the unit place be y

the number will be 10x + y

sum of the digits is 11

x + y = 11 equ (1)

the number when interchange is 27 more than original number

10x + y = 10y + x - 27

10x + y - 10y - x = -27

9x - 9y = -27

9(x - y) = - 27

x - y = - 3 equ (2)

adding equ (1) + (2)

2x = 8

x = 8/2 = 4

substitute x in equation (1)

x + y = 11

4 + y = 11

y = 11 - 4

y = 7

the required number is

= 10x + y

= 10(4) + 7

= 40 + 7

= 47