The sum of the digit of two digit number is 12.If digit are interchanged and resuiting number is added to original number we get 132
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Let us assume, x and y are the two digit of the two-digit number
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 12 ----------------1
also given:
10x + y + 10y + x = 132
11x + 11y = 132
x + y = 12 -------------2
There is some problem in this....we can not solve this as both the equations are same.
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 12 ----------------1
also given:
10x + y + 10y + x = 132
11x + 11y = 132
x + y = 12 -------------2
There is some problem in this....we can not solve this as both the equations are same.
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