Question

the sum of the digit of two digit number is 5 if the digits are reversed the number is reduced by 27 find the number

Answer 1

Heya

Let the number be xy where x is the ten's digit and y is the unit's digit.

x+y=5......(1)

It can be written as 10x+y

[23 can be written as 10×2+3=20+3]


If the digits are reversed, the number becomes yx i.e 10y+x

According to the problem,

10y+x=10x+y-27

10y-y+x-10x=-27

9y-9x= -27

-9(x-y)= -27

x-y= -27/-9

x-y=3......(2)

(1) + (2)

x+y=5
x-y=3
---------
2x=8

x=8/2

x=4

Substituting x=4 in eq (1)

x+y=5

4+y=5

y=1

The number is 41

Answer 2

Step-by-step explanation:

Assume , tens Digit = x and ones digit = y

x + y = 5

x = 5 - y

10y + x = 10x + y - 27

9y - 9x = -27

x - y = 3

5 - y - y = 3

2y = 2

y = 1

x = 5 - 1

x = 4

Number = 10*4+1 = 41