The sum of the digit of two numbers is 7 .if the number is decreased by 45 after reversing the digits find the numb
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Hey!!!
@Bansal here
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Let the ten's digit be x and unit digit be y
Then ATQ,
=> x + y = 7
=> x = 7 - y -------(1)
Also
=> 10x + y - 45 = 10y + x
=> 9x - 9y = 45
=> x - y = 5
Using (1) in above equation
=> 7 - y - y = 5
=> -2y = -2
=> y = 1
Using it in (1)
=> x = 7 - 1
=> x = 6
Thus Original number = 60 + 1
=> 61
___________
Hope this helps ✌️
Legally Good Morning :-)
@Bansal here
____________
Let the ten's digit be x and unit digit be y
Then ATQ,
=> x + y = 7
=> x = 7 - y -------(1)
Also
=> 10x + y - 45 = 10y + x
=> 9x - 9y = 45
=> x - y = 5
Using (1) in above equation
=> 7 - y - y = 5
=> -2y = -2
=> y = 1
Using it in (1)
=> x = 7 - 1
=> x = 6
Thus Original number = 60 + 1
=> 61
___________
Hope this helps ✌️
Legally Good Morning :-)
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