Question

the sum of the digitin a two digit number is 9 .the number obtained by interchanging the digit exceeds the original number by 27.find the number
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Answer 1

let the digit at tens place =x
the digit at ones place= y
A/Q
X+Y=9.
=y=9-x
the number= 10x+y

A/Q
10y+x=10x+y+27
9y-9x=27
9(9-x)-9x=27
81-9x-9x=27
-18x=27-81
-18x=-54
x=54÷18
x=3
y=9-3
y=6
the number=3×10+6
30+6
36