The sum of the digits in a two digits number is 11 . The number formed by interchanging the digits of the number will be 45 more than the original number.Find the original number.
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let no be XY
X+ Y = 11
NOW
YX = 45+ XY
10 Y + X = 45 + 10X +Y
9Y -9X = 45
Y-X = 5
ALSO Y+X = 11
SO, 2Y = 16
Y = 8
X = 8-5 = 3
So number is 38
X+ Y = 11
NOW
YX = 45+ XY
10 Y + X = 45 + 10X +Y
9Y -9X = 45
Y-X = 5
ALSO Y+X = 11
SO, 2Y = 16
Y = 8
X = 8-5 = 3
So number is 38
Number and digits are not same so u have to let two different data
YX=Y0 + X what is this and how it becames y and zero ?
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10 Y + X = 45 + 10X +Y