Question

The sum of the digits of 2- digit number is 6 .on reversing the digit the number is obtain is less then 18 then the number is ?​

Answer 1

Answer:

Step-by-step explanation:

Hey mate here is your answer!

Let's set up a system with two variables: x = tens place of our answer, y = units place of our answer.

Digit sum of a two digit number is 6:

x+y=6 ,

Reverse the digits and you get 18 less than the original value:

10y+x=10x+y-18 ,

Now let's solve:

y=6-x ,

10(6-x)+x=10x+(6-x)-18 ,

60-10x+x=10x+(6-x)-18 ,

60-9x=9x-12 ,

72=18x ,

x=4 ,

y=6-4 ,

y=2 .

So our original number was 42. Sum of digits is 6. Swap the order of the digits to make 24, and you have a number 18 less than the original number.

Hope it helps you and please do mark me as Brainliest!

Answer 2

let 2 digit number=10 X+y

reversing digits=10y+X

according to the problem

X+y=6 -(1)

10x+y-18=10y+X

10x-x+y-10y-18=0

9x-9y-18=0

divide by 9

x-y-2=0

x-y=2 -(2)

Subtract (2) from (1)

X+y=6

x-y=2

(-)(+)(-)

2y=4

y=4/2

y=2

from (2)

x-y=2

x-2=2

X=2+2

X=4

the number=10x+y

=10(4)+2

=40+2

=42