The sum of the digits of 2- digit number is 6 .on reversing the digit the number is obtain is less then 18 then the number is ? solve it in 1 variable
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Digit sum of a two digit number is 6: x+y=6. Reverse the digits and you get 18 less than the original value: 10y+x=10x+y-18. Now let's solve:.
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