The sum of the digits of 2-digits number is 7. If the digits are reversed ,the new number is equal to 3 less than 4 times the original number find
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let x be the tens digit and y be the unit digit
Original Number=10x + y
x + y=7 (given)...........................................................eq1
Reverse Number=10y + x
10y + x = 4(10x + y) - 3 (given)
10y + x = 40x + 4y - 3
39x - 6y = 3
13x - 2y = 1..................................................eq2
After solving eq1 and eq2, we get
x = 1 , y = 6
So,Original number=16
New Number=61
Punjabitrap:
hey bro
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