Question

The sum of the digits of a 2 digit number is 12. The number obtained by interchanging the 2 digits exceeds the given number by 18. Find the numbers.

Answer 1

let the unit digit=x

let the ten digit=y

no=10x+y

reverse the no.

new no=10y+x

A.T.Q

(10x+y)-(10y+x)=18

9x -9y=18

x - y=18/9

x - y=2

x=2+y (1 value)

x+y=12

2y+y=12

3y=12

y=4

x=2+4

x=6

hence the original no=10x+y

10*6+4=64

reverse no=46