Question

The sum of the digits of a 2-digit number is 13. The number formed by jnterchanging the digits is 45 more than the original number. Find the
original number.​

Answer 1

Answer:

49

Step-by-step explanation:

Answer 2

Answer:

The number is ab=10a+b=xab=10a+b=x

10b+a=x+y10b+a=x+y

And there should be a solution

Subtracting both equations

9(b−a)=y9(b−a)=y

a+b=na+b=n

a=n−ba=n−b

9(b−a)=9(b−(n−b))=9(2b−n)=y9(b−a)=9(b−(n−b))=9(2b−n)=y

Or b=y+9n18b=y+9n18

a=n−y+9n18a=n−y+9n18

Now y=45, n=13 then b=9 a=4

49+45=94

Step-by-step explanation:

Hope this helps u....