Math, asked by abhineshpatel8165, 10 months ago

The sum of the digits of a 2 digit number is 17. if the number formed by reversing the digits is less than the original number by 9, find the original number.

Answers

Answered by harikairuvuru
3

Answer:

Therefore the original number is 89.

Step-by-step explanation:

Let us take digit at ten as x and unit digit as y.

original number=10x+y

Reversed number= 10y+x

Given sum of digits of original number is 17

x+y=17        --->(1)

The number formed by reversing the digits is less than the original number by 9

10x+y+9=10y+x

9x-9y=-9

divided both sides with 9

x-y= -1      --->(2)

add eq 1 and eq 2

x+y+x-y=17-1

2x=16

x=8

put x=8 in 1

8+y=17

y=9

Therefore the original number is 89.

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