The sum of the digits of a 2 digit number is 17. if the number formed by reversing the digits is less than the original number by 9, find the original number.
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Answer:
Therefore the original number is 89.
Step-by-step explanation:
Let us take digit at ten as x and unit digit as y.
original number=10x+y
Reversed number= 10y+x
Given sum of digits of original number is 17
x+y=17 --->(1)
The number formed by reversing the digits is less than the original number by 9
10x+y+9=10y+x
9x-9y=-9
divided both sides with 9
x-y= -1 --->(2)
add eq 1 and eq 2
x+y+x-y=17-1
2x=16
x=8
put x=8 in 1
8+y=17
y=9
Therefore the original number is 89.
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