The sum of the digits of a 2-digit number is 6. On reversing its digits, the number is 18 less than the
9. The sum of the digits of a 2-digit number is 9. On reversing its digits, the new number obtained is 45
original number. Find the number.
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Step-by-step explanation:
et's set up a system with two variables: x = tens place of our answer, y = units place of our answer.
Digit sum of a two digit number is 6:
x+y=6
Reverse the digits and you get 18 less than the original value:
10y+x=10x+y-18
Now let's solve:
y=6-x
10(6-x)+x=10x+(6-x)-18
60-10x+x=10x+(6-x)-18
60-9x=9x-12
72=18x
x=4
y=6-4
y=2
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