Math, asked by kartik22102016, 1 month ago

The sum of the digits of a 2-digit number is 6. On reversing its digits, the number is 18 less than the
9. The sum of the digits of a 2-digit number is 9. On reversing its digits, the new number obtained is 45
original number. Find the number.​

Answers

Answered by bhanishvarma12
3

Step-by-step explanation:

et's set up a system with two variables: x = tens place of our answer, y = units place of our answer.

Digit sum of a two digit number is 6:

x+y=6

Reverse the digits and you get 18 less than the original value:

10y+x=10x+y-18

Now let's solve:

y=6-x

10(6-x)+x=10x+(6-x)-18

60-10x+x=10x+(6-x)-18

60-9x=9x-12

72=18x

x=4

y=6-4

y=2

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