Question

The sum of the digits of a 2-digit number is 8. The number obtained by
interchanging the digits exceeds the given number by 18. Find the given numbers.​

Answer 1

Answer:

Let the digit at unit and ten's place be a and b

a+b=8

a=8-b------(1)

Original number=10b+a

Interchanged number {10a+b)

A/q. 10a+b-10b-a=18

9(a-b)=18

8-b-b=2. (using 1)

6=2b

b=3

a=8-3=5

Given number=35

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Answer 2

Step-by-step explanation:

let the number be 10x+y

now, sum of digits is 8 so

x+y =8

x=8-y

let number interchanged by the digits be 10y+x

10y+x-10x-y= 18

9y-9x=18

y-x=2

putting value of x which we earlier found

y-8+y= 2

2y=2+8

y=10/2=5

x=3

therefore first number will be 35 and second will be 53