Question

The sum of the digits of a 2 digit numberis 12.if the new number formed by reversing its digits is greater than the original no by 54 find the original no

Answer 1

Let the unit and tens digits be x and y respectively.
Number will be 10y+x.
After reversing digits , New number = 10x+y.
As per the question,
10x+y -(10y+x) = 54
10x+y -10y-x = 54
9x-9y = 54
9(x-y) = 54
x-y = 6.
And , x+y = 12 ,given in the question.
So, By solving both of the equations, you will get x=9 and y = 3.
Thus, the original number will be 39.

......Hope it will help.......