The sum of the digits of a 2-digits number is 7.If the digits are reversing ,the new number increased by 3 less than 4 times the original number . Find the original number.
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1
Answer:
16
Explanation:
Let the units place digit and tens place digit = x and y respectively.
Therefore, the desired number = 10 y + x
According to the problem:
x + y = 7 and 10 x + y = 4(10 y + x) - 3
{Eqn 1} ⇒ 10 x + y = 40 y + 4x -3
⇒ 6 x - 39 y = - 3 {Eqn 2}
On solving both the equations, we get:
x = 6 and y = 1
Therefore, the desired number = 10 y + x = 10 (1) + 6
Which is nothing but 16..
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