Math, asked by karthik5117, 9 months ago

the sum of the digits of a 2- digits number obtained by interchanging the digits exceed the given number by 18 . Find the given number​

Answers

Answered by DwitiyaRoy
2

Answer:

99

Step-by-step explanation:

hey friend,

if we interchange two digits then also the Sum remains the same so we divide18 by 2 (as its a2 digit no).The ans comes 9.By reapeating the digit we get the ans.

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Answered by llitzsanull
2

Step-by-step explanation:

Given

The sum of the digits of a 2 digit number is 8.

The number formed by interchanging the digits exceeds the given number by 18.

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To Find

The given numbers.

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Solution

Let the one's digit number be 'x' and the ten's digit be '8 - x'

Original Number → 10 (Ten's Digit) + 1 (One's Digit)

\sf \implies 10(8-x)+1(x)⟹10(8−x)+1(x)

\sf \implies 10(8) - 10(x) + x⟹10(8)−10(x)+x

\sf \implies80-10x+x⟹80−10x+x

\sf \implies80-9x⟹80−9x

After Interchanging the digits,

One's digit → 8 - x

Ten's digit → x

New Number → 10 (Ten's Digit) + 1 (One's Digit)

\sf \implies 10(x) + 1(8-x)⟹10(x)+1(8−x)

\sf \implies 10x+ 8 - x⟹10x+8−x

\sf \implies 9x + 8⟹9x+8

So, as the question states, when the digits of the original numbers are interchanged the new number exceeds by 18.

New number - Original Number = 18

Let's solve the equation step-by-step

\sf 9x + 8 -(80-9x) = 189x+8−(80−9x)=18

Step 1: Simplify the equation.

\sf \implies 9x + 8 -(80-9x) = 18⟹9x+8−(80−9x)=18

\sf \implies 9x + 8 - 80 + 9x = 18⟹9x+8−80+9x=18

Step 2: Combine Like Terms.

\sf \implies 9x + 8 - 80 + 9x = 18⟹9x+8−80+9x=18

\sf \implies (9x + 9x)+ (8 - 80) = 18⟹(9x+9x)+(8−80)=18

\sf \implies 18x-72=18⟹18x−72=18

Step 3: Add 72 to both sides of the equation.

\sf \implies 18x-72+72=18+72⟹18x−72+72=18+72

\sf \implies 18x=90⟹18x=90

Step 4: Divide 18 to both sides of the equation.

18x/18=90/18

∴ x = 5

∴ One's digit ⇒ x = 5

∴ Ten's digit ⇒ 8 - x = 8 - 5 = 3

∴ Original number ⇒ 35

∴ New Number ⇒ 53

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