Question

the sum of the digits of a 2digits number is 9.on reversing its digit the New number obtained is 45 more than the original number. find the number

Answer 1

hey dear



here is your answer



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Let the digit at unit place be x



Digit at ten place is y



Number = 10 y + x



so,


x + y = 9. ( 1)



If the number reversed so digit at unit place Y



Digit at ten place is x


so new number is 10x + y



new number is 45 more than the original number



10x + y = 10y + x +45




10x - x 10y - y = 45



9x - 9y = 45



x - y = 45 / 9


x - y = 5. ( 2)




x = 5 + y



substitute x = 5 + y in equation 1



x + y = 9


5 + y + y = 9


5 + 2y = 9



2y = 9 -5


y = 4 /2


y = 2




so, x + 5 + y


x + 5 + 2


x = 7





so , x = 7 and y = 2




so original number = 10 y + x


hence = 10 * 7 + 2



so, original number is = 70 + 2 = 72



original number is 72



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hope it helps


thank you