Question

the sum of the digits of a digit number is 8 . when 18 is added to the number , the digits interchange their place . find the two digit number . ​

Answer 1

Answer:

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Step-by-step explanation:

So the digit in tens place = 3 the digit in ones place is (8 - 3 = 5) , then the number is 35 and when 18 is added the result is 53, the digits interchange their position in the new number. Ans: 35

Answer 2

Solution :-

$\: \: \: \: \: \:$

$\begin{gathered} \begin {cases}\text \blue{Let one of the number be x} \\\text \blue{And the other number be 8 - x}\end{cases}\end{gathered}$

$\rm \red{According \: to \: the \: question}$

$\implies \sf{10x + (8 - x) + 18 = 10(8 - x) + x}$

$\implies \sf{ 10x + 8 - x + 18 = 80 -10x + x}$

$\implies \sf{9x + 26 = 80 - 9x}$

$\implies \sf{9x + 9x = 80 - 26}$

$\implies \sf{18x = 54}$

$\implies \sf{ x = \frac{54}{18} }$

$\huge \sf\boxed{ \purple{ \sf{x = 3}}}$

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