the sum of the digits of a number is subtracted from a number , the resulting number is always divisible by
a)2
b)5
c)8
d)9
and why ? show the working
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Let the number be xy , that is 10x+y .
Given, Sum of digits = x + y.
Question : The sum of digits of a number is subtracted from a number, the resulting number is always divisible by.
Number - Sum of digits
= ( 10 x + y) - ( x + y)
= 10x + y - x - y
= 9x .
So , 9x has factors 9 & x. Therefore, 9x is always divisible by 9 .
The sum of the digits of a number is subtracted from a number , the resulting number is always divisible by 9 .
Let the number be xy , that is 10x+y .
Given, Sum of digits = x + y.
Question : The sum of digits of a number is subtracted from a number, the resulting number is always divisible by.
Number - Sum of digits
= ( 10 x + y) - ( x + y)
= 10x + y - x - y
= 9x .
So , 9x has factors 9 & x. Therefore, 9x is always divisible by 9 .
The sum of the digits of a number is subtracted from a number , the resulting number is always divisible by 9 .
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