Question

The sum of the digits of a two - digit mumber is 12. if the new number is formed by reversing the digits is greater than the original number by 18. fnd the original number and also vheck your solution.

Answer 1

let the ones digit be ,x
then tens digit=(12-x)
original number=10(12-x)+x
= 120-10x +x
= 120-9x
reversed number =10(x)+(12-x)
= 10x+12-x
= 9x+12
ACCORDING TO THE QUESTION
(9x+12)-(120-9x) = 18
9x+12-120+9x = 18
18x-108 = 18
18x = 18+108
18x = 126
x = 126/18
x = 7
therefore original number= 120-9x
= 120- 9*7
= 120-63
= 57
verification

ones +tens digit = 12
5+7=12
12=12
since LHS=RHS
```HENCE VERIFIED```