Question

The sum of the digits of a two digit no is 11 .If the digits are reversed then the number increases by 27 . Find the number

Answer 1

Answer:

let the tenth place be x and the units place be y

the no.=10x+y

              x+y=11   -(1)

if the digits are reversed unit=x and tenth place =y

the no.=10y+x

(10x+y) +27=10y+x

10y+x - 10x-y=27

9y-9x=27

9(y-x)=27

y-x=3(27divided by 3)

-x +y=3  -(2)

x + y = 11

-x+y  =  3

---------------

0+2y=14

 2y=14

y=7

y=7 in equation (1)

x+y=11

x+7=11

x=11-7

x=4

hence the no.=10x+y

                    =10(4)+7

                    =40 + 7

                    =47

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