the sum of the digits of a two digit no is 12 and if 18 is addedd to the digit the digits are reversed. find the no
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2
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Step-by-step explanation:
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4
Answer:
57
Step-by-step explanation:
Let x be the one's digit and y be the ten's digit.
therefore number = 10y + x
According to question,
x + y = 12 …. (1)
If 18 is added to the digit the digits are reversed
10y + x + 18 = 10x + y
=> 9y -9x=-18
=> y - x = 2 ---- (2)
Solve (1) and (2), we get
x + y = 12
-x + y = 2
----------------
2y = 14
y = 7
Place y = 7 in (2), we get
=> y - x = 2
=> 7 - x = 2
=> x = 5
Therefore, the number = 57.
Hope it helps!
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