Question

the sum of the digits of a two digit no.is12.if the digits reversed,the new no is 12 less than twice the original no.find the no.

Answer 1

Answer:

as the sum of the digits is 12

x+y=12 ________(1)

x=12-y

the original number is 10x+y

10y+x=12-2(10x-y)

10y+x=12-20x+2y

8y+21x-12=0

put the value and get the answer

Answer 2

Step-by-step explanation:

please refer to the attachment

I hope it would help you

thank you