the sum of the digits of a two digit number is 10 and if 18 is subtracted from it the digits in resulting number are same find the number
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Let the Ten's digit be x and Unit's digit be y
ORIGINAL NUMBER = 10x + y
ACCORDING TO QUESTION,
x + y = 10 -------------(i)
10x + y - 18 = 10y + x ---------(ii)
Solving (ii)
9x - 9y = 18
Dividing by 9
x - y = 2 ----------- (iii)
ADDING (i) & (iii)
x + y = 10
x - y = 2
_____________
2x = 12
x = 6
Substituting x in eq (i)
6 + y = 10
y = 4
ORIGINAL NUMBER = 10x + y
=> 10 Ć 6 + 4
=> 64
>>>>>>>>>>>>>>>>>>>>>
ANSWER = 64
>>>>>>>>>>>>>>>>>>>>>>
ORIGINAL NUMBER = 10x + y
ACCORDING TO QUESTION,
x + y = 10 -------------(i)
10x + y - 18 = 10y + x ---------(ii)
Solving (ii)
9x - 9y = 18
Dividing by 9
x - y = 2 ----------- (iii)
ADDING (i) & (iii)
x + y = 10
x - y = 2
_____________
2x = 12
x = 6
Substituting x in eq (i)
6 + y = 10
y = 4
ORIGINAL NUMBER = 10x + y
=> 10 Ć 6 + 4
=> 64
>>>>>>>>>>>>>>>>>>>>>
ANSWER = 64
>>>>>>>>>>>>>>>>>>>>>>
anurag40:
man thanks for the effort but your answer is wrong
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