Question

The sum of the digits of a two digit number is 10 and the digit at unit place is two third of the digit at tens place find the number.

Answer 1

Answer:

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Step-by-step explanation:

Let the 10s digit of two digit number be x and 1s digit be y

Hence the number is 10x + y

The number of two digits if a two digit number is 10. It means

x + y = 10…Eq.1

The digit at the unit place is 2/3rd of the digit at the tens place

y = 2/3x

y = 2x/3.. Eq .2

Now substituting the value of y from Eq.. 2 to Eq..1

x + y = 10

x + 2x/3 = 10

(3x + 2x)/3 = 10

Cross multiplication

5x = 30

x = 30/5

x = 6

The 10s digit is 6

Substituting value of x in Eq..2 to drive value of y

y = 2x/3

y = 2 × 6/3

y = 2 × 2

y = 4

The 1s digit is 4

Thus the number is 64.

Answer the number is 64

Answer 2

Answer:

Number is 64

Step-by-step explanation:

Let the number be xy =10x +y

Given

y =2/3x

x +y =10

x + (2/3)x =10

(5/3)x =10

x = 10*3/5= 6

x =6

y =(2/3)6=4

So the number is 64