Question

The sum of the digits of a two digit number is 10 and the digit at units place is 2/3rd of the digit at tens place. Find the number.​

Answer 1

Answer:

64

Step-by-step explanation:

First of all there is error in first line that there is the sum in place of the number at the beginning of question

Let xy be the number .

According to the question - x + y = 10 ………….(1)

and y = (2÷3)x …………………..(2)

When we put value of y from equation (2) to equation (1) we get , x + (2÷3)X= 10 and on solving this we get

x = 6 , and from equation (1) we get y = 4 so, the number is 64.

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Answer 2

Given :

• Sum of two digits = 10
• Unit's digit = 2/3 × Ten's digit

To find :

• The number.

Solution :

Let, the ten's digit = x

Then, unit's digit = 2/3 × x

→ 2x/3

According to question,

Sum of the digits is equal to 10.Therefore,

→x + 2x/3 = 10

→(3x+2x)/3 = 10

→5x/3 = 10

→x = (10×3)/5

→x = 30/5

→x = 6

Hence,

• Ten's digit = 6

And we have,

• Unit's digit = 2/3 × Ten's digit

→ (6× 2/3) = 4

Hence,

The number is 64

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