The sum of the digits of a two digit number is 10 and the digit at unit place is two third of the digit at tens place find the number
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The number is 64
Given data :
Sum of two digits = 10
Unit's digit = 2/3 × Ten's digit
Let,
The ten's digit = x
And, unit's digit = 2/3 × x = 2x/3
So,
x + 2x/3 = 10
(3x+2x)/3 = 10
5x/3 = 10
x = (10×3)/5
x = 30/5
x = 6
So, Ten's digit = 6
Unit's digit = (6× 2/3) = 4
So,the number = 64 (Answer)
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