Question

the sum of the digits of a two digit number is 10. if 18 be subtracted from it the digits in the resulting number will be equal.the number is

Answer 1

x = 10's digit of a two digit number(Let)
 y = units digit(Let)
n=Resulting equal digits(Let)
Condition 1-the sum of a two digit number is 10
x + y = 10
further simplifying
y = (10-x)
 Condition 2-if 18 be subtracted from it the digits in the resulting number will be equal
10x + y - 18 = 10n + n
10x + y = 11n+ 18
Substitutituting values found above
10x + (10-x) = 11n + 18
10x - x = 11n + 18 - 10
9x = 11n+ 8

If we solve it we will found the values as - x = 7, y = 3, z = 5 and finally we can say the no. is 73.

Answer 2

Let the tens 's digit of a two digit number be x let the units digit be y Let the Resulting equal digits be n Condition 1-the sum of a two digit number is 10 x + y = 10 further simplifying y = (10-x) Condition 2-if 18 be subtracted from it the digits in the resulting number will be equal 10x + y - 18 = 10n + n 10x + y = 11n+ 18 Substitutituting values found above 10x + (10-x) = 11n + 18 10x - x = 11n + 18 - 10 9x = 11n+ 8 If we solve it we will found the valu