Question

The sum of the digits of a two digit number is 10. If the number formed By reversing the digits is less than the original number by 36, find the number

Answer 1

Let the digit in tens place be 'x' and the digit in units place be 'y'.
Therefore, the number= 10x+y
As per first condition,
x+y=10...... (1)
As per second condition,
10y+x=10x+y-36
9x-9y=36
x-y=4......(2)
Add eq(1) and (2),
2x=14
x=7
Now substitute x=7 in eq(1),
7+y=10
y=3
Number = 73