Question

the sum of the digits of a two-digit number is 10 if the number formed by reversing the digit is less than the original number by 18 find the original number

Answer 1

Let the two digit number is 10X+Y
Given sum of two digits=10
X+Y=10 ...........eq-1
number formed by reversing the digits is 18 less than the original.
10Y+X+18=10X+Y
=>9X-9Y=18 ..........eq-2
solving eq-1 and 2
X=6 and Y=4

Answer 2

Answer:

Let the two digit number is 10x + y

Given

Sum of two digits = 10

x + y = 10 -------- (i)

Number formed by reversing the digits is 18 less than the original.

10y + x + 18 = 10x + y

= 9x - 9y = 18 -------(ii)

Solving equation -(i) & (ii)

x = 6 and y = 4

So the original number is

64