The sum of the digits of a two-digit number is 10 .The number obtained by interchanging its digit is 1 less than twice the original number. find the number.
Answers
Answer:
Let first digit be x and second digit be y
∴x+y = 10--------(1)
10y+x = 2(10x+y)-1
=> 10y+x = 20x+2y-1
=> 8y-19x = -1-----(2)
(1)×8 = 8x+8y = 80
- (2)×1 = 8y-19x = -1
-------------------------------------
27x = 81
=> x = 81/27
= 3
Putting x=3 in (1)
3+y = 10
=> y = 7
∴ The number is 37.
Answer:
37 is the Answer
37 is the Answer Step-by-step explanation:
37 is the Answer Step-by-step explanation:Let x be the tens digit, and let y be the ones digit. It is easy to see that x + y = 10, and that the "original" number is 10x + y. The statement "If the digits are reversed, a new number is formed which is 1 less than twice the original number." is expressed by the equation 2(10x + y) - 1 = 10y + x. If you substitute 10 - x for y in this equation and solve, you get x = 3. Thus y = 7, so the original number is 37.
37 is the Answer Step-by-step explanation:Let x be the tens digit, and let y be the ones digit. It is easy to see that x + y = 10, and that the "original" number is 10x + y. The statement "If the digits are reversed, a new number is formed which is 1 less than twice the original number." is expressed by the equation 2(10x + y) - 1 = 10y + x. If you substitute 10 - x for y in this equation and solve, you get x = 3. Thus y = 7, so the original number is 37.Thank You For Attending