Question

The sum of the digits of a two digit number is 10. The number formed by reversing the digits is 18 less than the original number. Find the original number?​

Answer 1

Answer:

64

Step-by-step explanation:

64-46=18

6+4=10

 Let one's digit and ten's digit be x &y

No.=10y+x

Given     x+y=10------------------------(1)

reversing the digits

new no.=10x+y

10x+y=10y+x-18

9x-9y=-18

x-y=-2-------------------------------------(2)

                                (1)+(2)

                                   2x=8

                                      x=4

              substitute in (1)

                       then y=6

Hence  original no. is 10y+x=60+4=64

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Answer 2

✬ Fraction = 3/7 ✬

Step-by-step explanation:

Given:

• Numerator of a fraction is 4 less than its denominator.
• Fraction becomes 1/8 after increasing denominator by 1 and decreasing numerator by 2.

To Find:

• What is the original fraction ?

Solution:

• Let the numerator be x and denominator be y. Therefore fraction will be x/y.

➟ Numerator = 4 less than x

➟ x = (y – 4)

Now, decreasing numerator by 2

• New numerator = (x – 2)

Increasing denominator by 1.

• New denominator = (y + 1)

New (numerator/denominator) = 1/8

⟹ (x – 2)/(y + 1) = 1/8

⟹ 8(x – 2) = (y + 1)

⟹ 8x – 16 = y + 1

⟹ 8(y – 4) – 16 = y + 1

⟹ 8y - 32 - 16 = y + 1

⟹ 8y - 8 - 48 = 1

⟹7y = 49

⟹ y = 7

So,

• Denominator is 7.

• Numerator is (7 – 4) = 3.

Hence, fraction was 3/7.