The sum of the digits of a two-digit number is 11. If we interchange the digits, then the new number formed is 45 less than the original. Find out the original number.
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Suppose the first digit of no. Be x,then the e.q.
Will be as:
10(11-x)+x
Exchange the digits
10x + 11-x= -10(11-x)+45
Simplify it
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Hope you guys can understand this . Pls dont mind my handwriting. Thnx all the best
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