The sum of the digits of a two digit number is 12. If the new number formed by reversing the digits is greater than the original number by 18, find the original number.
LouisAaron:
I have the entire answer written ..... Let me answer this question
The answer by hari58 is wrong
Answers
Answered by
5
Let the 2 digit no. be 10x+y
x+y=12 ......(1)
new no. formed by reversing the digits= 10y+x
10y+x-(10x+y)=18
10y+x-10x-y=18
9y-9x=18 ........(2)
take 9 common in 2 equation....
it will become ....
y-x=2
from equation 1.... x=12-y
putting this value of x in 2 equation....
y-x=2
y-(12-y)=2
y-12+y=2
2y-12=2
2y=2+12
2y=14
y=7
putting this value of y in 2 equation.....
y-x=2
7-x=2
x=7-2
x=5
10x+y=50+7=57
x+y=12 ......(1)
new no. formed by reversing the digits= 10y+x
10y+x-(10x+y)=18
10y+x-10x-y=18
9y-9x=18 ........(2)
take 9 common in 2 equation....
it will become ....
y-x=2
from equation 1.... x=12-y
putting this value of x in 2 equation....
y-x=2
y-(12-y)=2
y-12+y=2
2y-12=2
2y=2+12
2y=14
y=7
putting this value of y in 2 equation.....
y-x=2
7-x=2
x=7-2
x=5
10x+y=50+7=57
thanks bro
not bro sir.....sister
:-)
can u plzz mark it as brainliest
Answered by
2
check this page . These are the basics to understand the Problems.
On order to solve such Problems first you should know how to form Two digit number Expression
On order to solve such Problems first you should know how to form Two digit number Expression
Attachments:
Similar questions