The sum of the digits of a two digit number is 12 .If the new number formed by reversing the digits is greater than the original number by 54, find the original number.
Answers
Required Answer:-
Given:
- The sum of the digits of a two digit number is 12.
- The new number formed by reversing the digits is greater than the original number by 54.
To find:
- The number.
Solution:
Let the unit digit of the number is y and the tens digit of the number be x.
Therefore,
➡ x + y = 12 ......(i)
➡ Number = 10x + y
➡ Reversed Number = 10y + x
According to the given condition,
➡ 10y + x - (10x + y) = 54
➡ 9y - 9x = 54
➡ 9(y - x) = 54
➡ y - x = 6 ........(ii)
Adding equations (i) and (ii), we get,
➡ 2y = 12 + 6
➡ 2y = 18
➡ y = 9
Hence,
x = 12 - y
= 12 - 9
= 3
Hence, the number is,
= 10 × 3 + 9
= 39
Answer:
- The number is 39.
Verification:
Let us verify our result.
Sum of the digits,
= 3 + 9
= 12 which is correct.
Reversed number = 93
93 - 39
= 54 which is also right.
Hence, 39 is the original number (Hence Verified)
The sum of the digits of a two digit number is 12 .If the new number formed by reversing the digits is greater than the original number by 54, find the original number.
Let the digit in ones place be x
So, the digit in tens place be 12 - x
Original no.
= 10(12 - x) + 1(x)
= 120 - 10x + x
= 120 - 9x
New no.
= 10(x) + 1(12 - x)
= 10x + 12 - x
= 9x + 12 [∵By reversing the digits]
According to Question,
New no. - Original no. = 54
(9x + 12) - (120 - 9x) = 54
⇒ 9x + 12 - 120 + 9x = 54
⇒ 18x - 108 = 54
⇒ 18x = 54 + 108
⇒ 18x = 162
⇒ x = 162 / 18
⇒ x = 9
Required Numbers -
Original no. = 120 - 9x = 120 - 9(9)
= 120 - 81 = 39
New no. = 93 [∵By reversing the digits]
Hence, the required number is either 39 or 93
Check -
(i)...According to Question,
The sum of the digits of the two-digit number is 12
The digits are 3 and 9
∴ Sum of digits = 3 + 9 = 12
Hence, the require numbers are correct
(ii)... According to Question,
The new number is greater than Original number by 54
New number = 93
Original number = 39
∴ Clearly, 39 < 93
∴ 93 - 39 = 54