the sum of the digits of a two-digit number is 12 .if the new number formed by reversing the digits is greater than the original number by 54.find the original number.check your solution.
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Answer:
origanal no.=39 and No. when digits reversed=93
Step-by-step explanation:
let x and y the digits
x+y=12 {given}
54+(10x+y)=(10y+x)
54+10x+y=10y+x
9x-9y=-54
x-y=-6
x + y=12
x-y=-6
2x=6 (Simultaneous equation)
x=3
Therefore by= 12-3 = 9
39+54=93 (verified)
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