the sum of the digits of a two -digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54'find the original number. check your solution.
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Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝
Question:-the sum of the digits of a two -digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54'find the original number.
Solution:-)
Let to be 10' unit digit Number be X
Let to be 1 unit digit number be y
then,
X+Y=12. (1 St EQUATION)
According to the question
10x+y+54=10y+x
10x-x+y-10y=-54
9x-9y=-54
9(x-y)=-54
x-y=-54/9
x-y=-6
then,
x+y=12
x-y=-6
_______
2y=18
y=18/2
y=9
then,
x+y=12
x+9=12
x=12-9
x=3
So.,,,
10y+x
10(9)+3
90+3
93
Question:-the sum of the digits of a two -digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54'find the original number.
Solution:-)
Let to be 10' unit digit Number be X
Let to be 1 unit digit number be y
then,
X+Y=12. (1 St EQUATION)
According to the question
10x+y+54=10y+x
10x-x+y-10y=-54
9x-9y=-54
9(x-y)=-54
x-y=-54/9
x-y=-6
then,
x+y=12
x-y=-6
_______
2y=18
y=18/2
y=9
then,
x+y=12
x+9=12
x=12-9
x=3
So.,,,
10y+x
10(9)+3
90+3
93
Answered by
12
Answer:
= 10y + 3
= 10(9+3)
= 90 + 30
= 120
Hope it will be helpful ✌️
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