The sum of the digits of a two digit number is 12. The number obtained by interchanging the digits exceeds the original number by 54. Find the original number
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Answered by
6
Answer:
let the tens place digit be 'x'and in unit place be'y'. therefore the no is 10x+y
according to the condition,
x+y = 12 or x= (12-y)
now the digit in unit place is x and tens place is y
therefore the no is (10y+x)
by the condition
10y+x = 10x+y+54
or 9x - 9y +54 =0
or 9(x - y + 6) =0
or 12-y - y+6 =0
or -2y +18 =0
or 2y=18
or y=9
therefore x= 12 -y
= 12-9= 3
therefore the original no is 10x +y =10*3+9=39
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Answer:
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