Math, asked by abhishekkumar856, 9 months ago

The sum of the digits of a two digit number is 12. The number obtained by interchanging the digits exceeds the original number by 54. Find the original number 

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Answers

Answered by dasarisahiti2416
6

Answer:

let the tens place digit be 'x'and in unit place be'y'. therefore the no is 10x+y

according to the condition,

x+y = 12 or x= (12-y)

now the digit in unit place is x and tens place is y

therefore the no is (10y+x)

by the condition

10y+x = 10x+y+54

or 9x - 9y +54 =0

or 9(x - y + 6) =0

or 12-y - y+6 =0

or -2y +18 =0

or 2y=18

or y=9

therefore x= 12 -y

= 12-9= 3

therefore the original no is 10x +y =10*3+9=39

Step-by-step explanation:

hope this helps u ❣️

Answered by 5honey
0

Answer:

search in Google dear dude

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