The sum of the digits of a two digit number is 12. the number obtained by reversing the digit is 36 greater than original number. find the number. please help it's urgent. anyone which answer this question i will mark his answer as brainliest
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lets say the no are x and second digit be 10y
so no is 10y+x
ao first equation is
x+y=12
the reversed no be 10x+y
so by second equation
10x+y=10y+x+36
10x-x-10y-y=36
9x-9y=39x
x-y=4
x=y+4
according to the first equation
x+y=12
so
x+(x+4)=12
2x+4=12
2x=12-4
2x=8
x=4
so
y=x+4
y=4+4
y=8 so no is
so no is 40+8=48 and 80+4=84
so no is 10y+x
ao first equation is
x+y=12
the reversed no be 10x+y
so by second equation
10x+y=10y+x+36
10x-x-10y-y=36
9x-9y=39x
x-y=4
x=y+4
according to the first equation
x+y=12
so
x+(x+4)=12
2x+4=12
2x=12-4
2x=8
x=4
so
y=x+4
y=4+4
y=8 so no is
so no is 40+8=48 and 80+4=84
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