The sum of the digits of a two digit number is 12 . The number ontained by interchanging the number exceeds the given number by 18 find the number
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Let the tens digit be 'x'
Then ones digit will be 'x-12'
Original no.= x*10+x-12
=11x-12
Interchanged no.= x-12*10+x
=2x-120
ATQ
(2x-120)-(11x-12)=18
2x-120-11x+12=18
9x-108=18
9x=18+108
x=126/9
x=14
Then ones digit will be 'x-12'
Original no.= x*10+x-12
=11x-12
Interchanged no.= x-12*10+x
=2x-120
ATQ
(2x-120)-(11x-12)=18
2x-120-11x+12=18
9x-108=18
9x=18+108
x=126/9
x=14
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