Math, asked by aditya952115, 9 months ago

the sum of the digits of a two digit number is 13 if the number is subtracted from the one obtained by interchanging the digits the result is 45 find the number​

Answers

Answered by aryankd36
3

Step-by-step explanation:

Given :-

The sum of two digit number is 13 .

if the number is subtracted from the one obtained by interchanging the digits the results is 45 .

Let

The two digits be x and y.

Number is 10x + y 

x + y = 13 (given)

y = 13 – x --------------1

A/q

10y + x – (10x + y) = 45

9y – 9x = 45

y – x = 5 --------------2

putting the value of y from equation 1 in eqn 2

13 – x – x = 5

13 – 2x = 5

2x = 8

x = 4✔

y = 13 – 4 = 9✔

The two-digit number = 10x + y = (10 × 4) + 9 = 49.

HOPE THIS WILL HELP YOU

Answered by Anonymous
0

Answer: 49

Step-by-step explanation:

let the unit's digit = x

and tenth digit = y

then number = 10y +x

so reverse number = 10x +y

reverse number - number = 45 (given)

10x+y -10y-x = 45

9x-9y = 45

x-y = 5 ..... (1)

now, it is given that x+y =13 (∵sum of digit is 13) ....(2)

solving (1) and (2) we get,  x =9 and y = 4

so the number is 49

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